2. 哈尔滨工业大学 航天工程系,哈尔滨 150001;
3. 上海宇航系统工程研究所,上海 201109
2. Dept.of Aerospace Engineering, Harbin Institute of Technology, Harbin 150001, China;
3. Aerospace System Engineering Shanghai, Shanghai 201109, China
多柔性连杆机械臂(multiple-flexible-link manipulator, MFLM)由于具有质量轻、惯量低等优点,在未来空间站建设、空间操控和在轨服务等任务中担任着重要的角色[1-4],同时也是实现装备制造等产业智能化的重要设备[5-6].然而,机械臂运动过程中,臂杆的柔性导致振动,影响定位精度; 刚体运动与结构振动高度耦合,呈现出强非线性; 关节驱动力矩需要同时实现关节转动和振动控制,属于欠驱动系统; 负载随着任务不同而不同,存在不确定性.本文针对采用柔性臂杆的机械臂的角度运动和振动抑制的控制器设计问题开展研究.
内外环的控制器设计是柔性机械臂常用的控制器设计方法.内环通过臂杆弯曲反馈消除其振动,外环采用角度反馈跟踪期望轨迹.比例微分(proportional derivative, PD)、比例微分积分(proportional integral derivative,PID)、自适应算法、积分阻抗技术、广义比例积分等被广泛用于内环和外环的控制器设计[7-9]; 基因学习算法[10]、逆模型控制[11]、力控制[12]、采用压电元件的主动振动控制[13]、H∞控制[14]等也都在MFLM的控制上得到了一定的应用.由于结构振动相对于关节的刚体转动要快很多,采用奇异摄动理论将整个复杂系统分解为快时标和慢时标两个相对简单的子系统,在柔性关节[15-18]、柔性臂杆[19-21]等机械臂的控制中得到了应用.考虑到很难获得MFLM的精确动力学模型,自抗扰控制(active disturbance rejection control,ADRC)[21-23]通过扩张状态观测器(extended state observer,ESO)扩展一个状态实现对内部和外部干扰的估计和补偿,采用反馈控制器实现一定的鲁棒性能. ADRC通过质量矩阵可以实现系统的自解耦.但是,末端负载的不确定性导致质量矩阵的不确定,引起ADRC的性能下降.频域辨识和模态滤波器广泛用来解决柔性连杆机械臂末端负载的不确定性[24-26].
本文在对MFLM系统进行时标分解的基础上,内环快时标子系统采用线性二次型(linear quadratic regulator,LQR)控制器,实现振动的快速抑制; 外环慢时标子系统设计了ADRC控制器,同时采用迭代最小二乘(recursive least-squares,RLS)算法实现对末端负载的估计和补偿.
1 系统建模如图 1所示,MFLM具有n个柔性连杆、n个关节和1个末端负载.臂杆i的长度为li,密度为ρi,刚度为EIi; 关节i的驱动力矩为τi,角位置记作θi.关节认为是集中质量,转动惯量等效到臂杆上,末端负载的质量为mi.采用Euler-Lagrange方法和假设模态法[21, 25],得到MFLM的动力学模型为
$ \mathit{\boldsymbol{M}}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{q}}} \right)\left[ {\begin{array}{*{20}{c}} {\mathit{\boldsymbol{\ddot \theta }}}\\ {\mathit{\boldsymbol{\ddot q}}} \end{array}} \right] + \mathit{\boldsymbol{H}}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{\dot \theta }},\mathit{\boldsymbol{q}},\mathit{\boldsymbol{\dot q}}} \right) + \left[ {\begin{array}{*{20}{c}} {\bf{0}}&{\bf{0}}\\ {\bf{0}}&\mathit{\boldsymbol{K}} \end{array}} \right]\left[ {\begin{array}{*{20}{c}} \mathit{\boldsymbol{\theta }}\\ \mathit{\boldsymbol{q}} \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} \mathit{\boldsymbol{\tau }}\\ {\bf{0}} \end{array}} \right], $ | (1) |
式中:M(θ, q)为质量矩阵,H(θ,
把质量矩阵M(θ, q)及其逆矩阵N(θ, q)、H(θ,
$ \begin{array}{l} \mathit{\boldsymbol{M}} = \left[ {\begin{array}{*{20}{c}} {{\mathit{\boldsymbol{M}}_{\theta \theta }}}&{{\mathit{\boldsymbol{M}}_{\theta q}}}\\ {\mathit{\boldsymbol{M}}_{\theta q}^{\rm{T}}}&{{\mathit{\boldsymbol{M}}_{\theta q}}} \end{array}} \right],\\ \mathit{\boldsymbol{N}} = \left[ {\begin{array}{*{20}{c}} {{\mathit{\boldsymbol{N}}_{\theta \theta }}}&{{\mathit{\boldsymbol{N}}_{\theta q}}}\\ {\mathit{\boldsymbol{N}}_{\theta q}^{\rm{T}}}&{{\mathit{\boldsymbol{N}}_{\theta q}}} \end{array}} \right], \end{array} $ |
$ \mathit{\boldsymbol{H}}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{\dot \theta }},\mathit{\boldsymbol{q}},\mathit{\boldsymbol{\dot q}}} \right) = \left[ {\begin{array}{*{20}{c}} {{\mathit{\boldsymbol{H}}_\theta }\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{\dot \theta }},\mathit{\boldsymbol{q}},\mathit{\boldsymbol{\dot q}}} \right)}\\ {{\mathit{\boldsymbol{H}}_q}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{\dot \theta }},\mathit{\boldsymbol{q}},\mathit{\boldsymbol{\dot q}}} \right)} \end{array}} \right], $ |
式(1) 可以进一步表示为
$ \begin{array}{l} \mathit{\boldsymbol{\ddot \theta }} = {\mathit{\boldsymbol{N}}_{\theta \theta }}\left( {\mathit{\boldsymbol{\tau }} - {\mathit{\boldsymbol{H}}_\theta }} \right) - {\mathit{\boldsymbol{N}}_{\theta q}}\left( {\mathit{\boldsymbol{K\theta + }}{\mathit{\boldsymbol{H}}_q}} \right),\\ \mathit{\boldsymbol{\ddot q}} = \mathit{\boldsymbol{N}}_{\theta q}^{\rm{T}}\left( {\mathit{\boldsymbol{\tau }} - {\mathit{\boldsymbol{H}}_\theta }} \right) - {\mathit{\boldsymbol{N}}_{qq}}\left( {\mathit{\boldsymbol{K\theta + }}{\mathit{\boldsymbol{H}}_q}} \right). \end{array} $ |
选择摄动参数为
$ {\mu ^{ - 1}} = \sqrt {{\mu _{\min }}\left( {{\mathit{\boldsymbol{N}}_{qq,0}}\mathit{\boldsymbol{K}}} \right)} , $ |
其中
$ \left\{ \begin{array}{l} \mathit{\boldsymbol{\ddot \theta }} = {\mathit{\boldsymbol{N}}_{\theta \theta }}\left[ {\mathit{\boldsymbol{\tau }} - {\mathit{\boldsymbol{H}}_\theta }\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{\dot \theta }},{\mathit{\boldsymbol{\mu }}^2}\mathit{\boldsymbol{z}},{\mathit{\boldsymbol{\mu }}^2}\mathit{\boldsymbol{\dot z}}} \right)} \right] - \\ \;\;\;\;\;\;{\mathit{\boldsymbol{N}}_{\theta q}}\left[ {\mathit{\boldsymbol{\tilde Kz + }}{\mathit{\boldsymbol{H}}_q}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{\dot \theta }},{\mathit{\boldsymbol{\mu }}^2}\mathit{\boldsymbol{z}},{\mathit{\boldsymbol{\mu }}^2}\mathit{\boldsymbol{\dot z}}} \right)} \right],\\ {\mathit{\boldsymbol{\mu }}^2}\mathit{\boldsymbol{\ddot z = N}}_{\theta q}^{\rm{T}}\left[ {\mathit{\boldsymbol{\tau }} - {\mathit{\boldsymbol{H}}_\theta }\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{\dot \theta }},{\mathit{\boldsymbol{\mu }}^2}\mathit{\boldsymbol{z}},{\mathit{\boldsymbol{\mu }}^2}\mathit{\boldsymbol{\dot z}}} \right)} \right] - \\ \;\;\;\;\;\;{\mathit{\boldsymbol{N}}_{qq}}\left[ {\mathit{\boldsymbol{\tilde Kz + }}{\mathit{\boldsymbol{H}}_q}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{\dot \theta }},{\mathit{\boldsymbol{\mu }}^2}\mathit{\boldsymbol{z}},{\mathit{\boldsymbol{\mu }}^2}\mathit{\boldsymbol{\dot z}}} \right)} \right]. \end{array} \right. $ | (2) |
将μ=0代入并整理,得到慢时标子系统为
$ {{\mathit{\boldsymbol{\ddot \theta }}}_{\rm{s}}} = - \mathit{\boldsymbol{M}}_{\theta \theta ,{\rm{s}}}^{ - 1}{\mathit{\boldsymbol{H}}_{\theta ,{\rm{s}}}}\left( {{\mathit{\boldsymbol{\theta }}_{\rm{s}}},{{\mathit{\boldsymbol{\dot \theta }}}_{\rm{s}}},0,0} \right) + \mathit{\boldsymbol{M}}_{\theta \theta ,{\rm{s}}}^{ - 1}{\mathit{\boldsymbol{\tau }}_{\rm{s}}}. $ | (3) |
下标‘s’表示慢时标子系统的物理量.
在获得快时标系统时,认为慢时标系统的物理量为常量,定义快时标子系统变量为zf:=z-zs,控制量为τf:=τ-τs, 式(2) 中快时标子系统可以写为
$ \frac{{{{\rm{d}}^2}{\mathit{\boldsymbol{z}}_{\rm{f}}}}}{{{\rm{d}}{\sigma ^2}}} = \mathit{\boldsymbol{N}}_{\theta q}^{\rm{T}}{\mathit{\boldsymbol{\tau }}_{\rm{f}}} - {\mathit{\boldsymbol{N}}_{qq}}\mathit{\boldsymbol{\tilde K}}{\mathit{\boldsymbol{z}}_{\rm{f}}}. $ |
其中σ=t/μ为快时标标度.
2 控制器设计图 2给出了控制器结构示意图,控制力矩为
$ \mathit{\boldsymbol{\tau }} = {\mathit{\boldsymbol{\tau }}_{\rm{s}}} + {\mathit{\boldsymbol{\tau }}_{\rm{f}}}. $ |
其中,慢时标控制量τs通过ADRC控制器给出,快时标控制量τf通过LQR控制器给出,末端负载的质量通过RLS算法估计并反馈至ADRC控制器.
2.1 末端负载的估计考虑到末段负载的不确定性,将质量矩阵重新表达为两部分
$ \mathit{\boldsymbol{M}}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{q}}} \right) = {\mathit{\boldsymbol{M}}_0}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{q}}} \right) + {\mathit{\boldsymbol{C}}_M}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{q}}} \right){m_n}. $ | (4) |
其中M0(θ, q)为确定的部分,CM(θ, q)为不确定负载mn的贡献系数,是与mn无关的量.同理,H(θ,
$ \mathit{\boldsymbol{H}}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{\dot \theta }},\mathit{\boldsymbol{q}},\mathit{\boldsymbol{\dot q}}} \right) = {\mathit{\boldsymbol{H}}_0}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{\dot \theta }},\mathit{\boldsymbol{q}},\mathit{\boldsymbol{\dot q}}} \right)\mathit{\boldsymbol{ + }}{\mathit{\boldsymbol{C}}_{\rm{H}}}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{\dot \theta }},\mathit{\boldsymbol{q}},\mathit{\boldsymbol{\dot q}}} \right){m_n}. $ |
将式4)-5) 带入到式(1) 中可得
$ {\mathit{\boldsymbol{ \boldsymbol{\varPhi} }}^{\rm{T}}}{m_n} = \mathit{\boldsymbol{\eta }}, $ |
其中:
$ \begin{array}{*{20}{c}} {{\mathit{\boldsymbol{ \boldsymbol{\varPhi} }}^{\rm{T}}} = {\mathit{\boldsymbol{C}}_M}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{q}}} \right)\left[ {\begin{array}{*{20}{c}} {\mathit{\boldsymbol{\ddot \theta }}}\\ {\mathit{\boldsymbol{\ddot q}}} \end{array}} \right]\mathit{\boldsymbol{ + }}{\mathit{\boldsymbol{C}}_{\rm{H}}}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{\dot \theta }},\mathit{\boldsymbol{q}},\mathit{\boldsymbol{\dot q}}} \right),}\\ {\mathit{\boldsymbol{\eta = }}\left[ {\begin{array}{*{20}{c}} \mathit{\boldsymbol{\tau }}\\ {\bf{0}} \end{array}} \right] - \left[ {\begin{array}{*{20}{c}} {\bf{0}}&{\bf{0}}\\ {\bf{0}}&\mathit{\boldsymbol{K}} \end{array}} \right]\left[ {\begin{array}{*{20}{c}} \mathit{\boldsymbol{\theta }}\\ \mathit{\boldsymbol{q}} \end{array}} \right] - {\mathit{\boldsymbol{H}}_0}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{\dot \theta }},\mathit{\boldsymbol{q}},\mathit{\boldsymbol{\dot q}}} \right) - {\mathit{\boldsymbol{M}}_0}\left( {\mathit{\boldsymbol{\theta }},\mathit{\boldsymbol{q}}} \right)\left[ {\begin{array}{*{20}{c}} {\mathit{\boldsymbol{\ddot \theta }}}\\ {\mathit{\boldsymbol{\ddot q}}} \end{array}} \right].} \end{array} $ |
考虑到在某些情况下, Φ≈0,同时为了充分利用旧数据信息,采用迭代最小二乘算法估计负载质量
$ \begin{array}{l} {{\dot m}_{n,k}} = {{\dot m}_{n,k - 1}} + {\mathit{\boldsymbol{G}}_k}\left( {{\mathit{\boldsymbol{\eta }}_k} - \mathit{\boldsymbol{ \boldsymbol{\varPhi} }}_k^{\rm{T}}{{\hat m}_{n,k - 1}}} \right),\\ {\mathit{\boldsymbol{G}}_k} = {P_{k - 1}}{\mathit{\boldsymbol{ \boldsymbol{\varPhi} }}_k}{\left( {\mathit{\boldsymbol{I + \boldsymbol{\varPhi} }}_k^{\rm{T}}{P_{k - 1}}{\mathit{\boldsymbol{ \boldsymbol{\varPhi} }}_k}} \right)^{ - 1}},\\ {P_k} = \left( {1 - {\mathit{\boldsymbol{K}}_k}\mathit{\boldsymbol{ \boldsymbol{\varPhi} }}_k^{\rm{T}}} \right){P_{k - 1}}. \end{array} $ |
在应用中,角度信息可以通过编码器测得,臂杆弯曲信息可以通过应变片测量,对于角度的导数和各阶模态坐标需要通过估计得到.这里采用跟踪微分器(tracking differentiator, TD):
$ \left\{ \begin{array}{l} {{\dot x}_1} = {x_2},\\ {{\dot x}_2} = fh\left( {{x_1} - u,{x_2},r,{h_0}} \right). \end{array} \right. $ |
式中:x1、x2是状态变量,u是控制输入,h0和r分别是滤波因子和速度因子,fh(x1, x2, r, h0)定义如下:
$ \begin{array}{l} d = r{h_0};\\ {d_0} = {h_0}d;\\ y = {x_1} + {h_0}{x_2};\\ {a_0} = \sqrt {{d^2} + 8r\left| y \right|} ; \end{array} $ |
$ \begin{array}{l} a = \left\{ \begin{array}{l} {x_2} + 0.5\left( {{a_0} - d} \right){\mathop{\rm sgn}} \left( y \right),\;\;\;\left| y \right| > {d_0};\\ {x_2} + y/{h_0},\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\left| y \right| \ge {d_0}; \end{array} \right.\\ fh = - \left\{ \begin{array}{l} r{\mathop{\rm sgn}} \left( a \right),\;\;\;\;\;\left| a \right| > d;\\ ra/d,\;\;\;\;\;\;\;\;\;\left| a \right| \le d. \end{array} \right. \end{array} $ |
慢时标子系统(3) 可以表达为
$ {{\mathit{\boldsymbol{\ddot \theta }}}_{\rm{s}}} = \mathit{\boldsymbol{f}}\left( \cdot \right) + \mathit{\boldsymbol{u}}, $ | (6) |
其中
$ \begin{array}{*{20}{c}} {\mathit{\boldsymbol{f}}\left( \cdot \right) = {{\left[ {\begin{array}{*{20}{c}} {{f_1}\left( \cdot \right)}&{{f_2}\left( \cdot \right)}& \cdots &{{f_n}\left( \cdot \right)} \end{array}} \right]}^{\rm{T}}} = }\\ { - \mathit{\boldsymbol{M}}_{\theta \theta ,{\rm{s}}}^{ - 1}{\mathit{\boldsymbol{H}}_{\theta ,{\rm{s}}}}\left( {{\mathit{\boldsymbol{\theta }}_{\rm{s}}},{{\mathit{\boldsymbol{\dot \theta }}}_{\rm{s}}},0,0} \right)} \end{array} $ |
表示总的干扰,包含内部不确定性和外部干扰;
$ \mathit{\boldsymbol{u = }}{\left[ {\begin{array}{*{20}{c}} {{u_1}}&{{u_2}}& \cdots &{{u_n}} \end{array}} \right]^{\rm{T}}} = \mathit{\boldsymbol{M}}_{\theta \theta ,{\rm{s}}}^{ - 1}{\mathit{\boldsymbol{\tau }}_{\rm{s}}}, $ | (7) |
是虚拟控制量.令xi1=θi, s、xi2=
$ \left\{ \begin{array}{l} {{\dot x}_{i1}} = {x_{i2}},\\ {{\dot x}_{i2}} = {f_i}\left( \cdot \right) + {u_i}. \end{array} \right. $ |
选择虚拟控制为
$ {u_i} = \left( {{{\ddot \theta }_{{\rm{d}}i}} - {{\hat x}_{i3}}} \right) + {k_{{\rm{d}}i}}\left( {{{\dot \theta }_{{\rm{d}}i}} - {{\hat x}_{i2}}} \right) + {k_{{\rm{p}}i}}\left( {{\theta _{{\rm{d}}i}} - {{\hat x}_{i1}}} \right). $ |
式中:kpi和kdi分别是比例和微分系数,θdi、
$ \left\{ \begin{align} & {{{\dot{\hat{x}}}}_{i1}}={{{\hat{x}}}_{i2}}-{{\beta }_{i1}}{{{\hat{e}}}_{i}}, \\ & {{{\dot{\hat{x}}}}_{i2}}={{{\hat{x}}}_{i3}}-{{\beta }_{i2}}{{{\hat{e}}}_{i}}+{{u}_{i}}, \\ & {{{\dot{\hat{x}}}}_{i3}}=-{{\beta }_{i3}}{{{\hat{e}}}_{i}}. \\ \end{align} \right. $ |
式中:βi1、βi2、βi3是状态估计器增益,
$ \begin{array}{l} \lambda \left( s \right) = {s^{2 + m}} + {\beta _{i1}}{s^{2 + m - 1}} + \cdots + {\beta _{i\left( {2 + m - 1} \right)}}s + {\beta _{i\left( {2 + m} \right)}} = \\ \;\;\;\;\;\;\;\;\;\;\;{\left( {s + {\omega _0}} \right)^{2 + m}}, \end{array} $ |
由此可以得到所有的增益系数.
假设状态估计是理想的,即
$ {{\ddot e}_{{\rm{p}}i}} + {k_{{\rm{d}}i}}{{\dot e}_{{\rm{p}}i}} + {k_{{\rm{p}}i}}{e_{{\rm{p}}i}} = 0. $ |
式中, epi=θdi-θi.因此,设计kpi和kdi, 使上述系统稳定且有期望的响应.
期望角速度和角加速度可以采用TD滤波器给出; 为了改善系统性能,误差项(
$ \begin{array}{l} fal\left( {x,\alpha ,\delta } \right) = \\ \left\{ \begin{array}{l} {\left| x \right|^\alpha }{\rm{sign}}\left( x \right),\;\;\;\;\left| x \right| > \delta ;\\ \frac{x}{{{\delta ^{1 - \alpha }}}},\;\;\;\;\;\;\;\;\;\;\;\;\;\left| x \right| \le \delta ; \end{array} \right.,\delta > 0,0 < \alpha < 1. \end{array} $ |
得到控制器为
$ \begin{align} & {{u}_{i}}=\left( {{{\hat{\ddot{\theta }}}}_{\rm{d}i}}-{{{\hat{x}}}_{i3}} \right)+{{k}_{\rm{d}i}}fal\left( {{{\hat{\dot{\theta }}}}_{\rm{d}i}}-{{{\hat{x}}}_{i2}},{{\alpha }_{\rm{d}i}},{{\delta }_{\rm{d}i}} \right)+ \\ & \ \ \ \ \ \ \ {{k}_{\rm{p}i}}fal\left( {{\theta }_{\rm{d}i}}-{{{\hat{x}}}_{i1}},{{\alpha }_{\rm{p}i}},{{\delta }_{\rm{p}i}} \right). \\ \end{align} $ |
根据式(7),同时考虑到末端负载的不确定性,mn采用估计值替代,对应的质量矩阵记作
$ {{\mathit{\boldsymbol{ }}\!\!\tau\!\!\rm{ }}_{\rm{s}}}={{{\mathit{\boldsymbol{\hat{M}}}}}_{\theta \theta ,\rm{s}}}\mathit{\boldsymbol{u}}. $ |
将快时标子系统表达为状态空间的形式为
$ {{{\mathit{\boldsymbol{\dot{x}}}}}_{\rm{f}}}={{\mathit{\boldsymbol{A}}}_{\rm{f}}}{{\mathit{\boldsymbol{x}}}_{\rm{f}}}+{{\mathit{\boldsymbol{B}}}_{\rm{f}}}{{\mathit{\boldsymbol{u}}}_{\rm{f}}}. $ |
其中
$ {\mathit{\boldsymbol{A}}_{\rm{f}}} = \left[ {\begin{array}{*{20}{c}} {\bf{0}}&\mathit{\boldsymbol{I}}\\ { - {\mathit{\boldsymbol{N}}_{qq}}\mathit{\boldsymbol{\tilde K}}}&{\bf{0}} \end{array}} \right],{\mathit{\boldsymbol{B}}_{\rm{f}}} = \left[ {\begin{array}{*{20}{c}} 0\\ {\mathit{\boldsymbol{N}}_{\theta q}^{\rm{T}}} \end{array}} \right],{\mathit{\boldsymbol{x}}_{\rm{f}}} = \left[ {\begin{array}{*{20}{c}} {{\mathit{\boldsymbol{z}}_{\rm{f}}}}\\ {\frac{{{\rm{d}}{\mathit{\boldsymbol{z}}_{\rm{f}}}}}{{{\rm{d}}\sigma }}} \end{array}} \right]. $ |
采用最优控制技术进行振动抑制,目标函数选择为
$ J = \frac{1}{2}\int_0^\infty {\left[ {\mathit{\boldsymbol{x}}_{\rm{f}}^{\rm{T}}{\mathit{\boldsymbol{Q}}_{\rm{f}}}{\mathit{\boldsymbol{x}}_{\rm{f}}} + \mathit{\boldsymbol{\tau }}_{\rm{f}}^{\rm{T}}{\mathit{\boldsymbol{R}}_{\rm{f}}}{\mathit{\boldsymbol{\tau }}_{\rm{f}}}} \right]{\rm{d}}t} . $ |
式中Qf和Rf为权重系数矩阵.采用标准的LQR设计,快时标系统的控制输出为
$ {\mathit{\boldsymbol{\tau }}_{\rm{f}}} = - {\mathit{\boldsymbol{K}}_{\rm{f}}}{\mathit{\boldsymbol{x}}_{\rm{f}}} + {\mathit{\boldsymbol{K}}_{\rm{f}}}\left[ {\begin{array}{*{20}{c}} {{z_{\rm{s}}}}\\ {\bf{0}} \end{array}} \right]. $ |
其中:
$ \mathit{\boldsymbol{K = }} - \mathit{\boldsymbol{R}}_{\rm{f}}^{ - 1}\mathit{\boldsymbol{B}}_{\rm{f}}^{\rm{T}}{\mathit{\boldsymbol{P}}_{\rm{f}}}\left( t \right). $ |
Pf通过求解Riccati方程获得:
$ {{\mathit{\boldsymbol{\dot P}}}_{\rm{f}}}\left( t \right) = - {\mathit{\boldsymbol{P}}_{\rm{f}}}\left( t \right){\mathit{\boldsymbol{A}}_{\rm{f}}} - \mathit{\boldsymbol{A}}_{\rm{f}}^{\rm{T}}{\mathit{\boldsymbol{P}}_{\rm{f}}}\left( t \right) + {\mathit{\boldsymbol{P}}_{\rm{f}}}\left( t \right){\mathit{\boldsymbol{B}}_{\rm{f}}}\mathit{\boldsymbol{R}}_{\rm{f}}^{ - 1}\mathit{\boldsymbol{B}}_{\rm{f}}^{\rm{T}}{\mathit{\boldsymbol{P}}_{\rm{f}}}\left( t \right) - {\mathit{\boldsymbol{Q}}_{\rm{f}}}. $ |
在仿真算例中,考虑具有两节柔性臂杆的机械臂,每节臂杆考虑两阶模态,相应的参数见表 1.仿真采用Simulink,通过四阶Runge-Kutta法求解,仿真步长0.000 5 s.
机械臂的操作空间为{(θ1, θ2)|θ1∈[0, 2π], θ2∈[0, 2π]},摄动参数计算为μ=0.016 7 s,系统的最小自然频率为59.8 rad/s,通过将所有的极点配置在-2.5,得到反馈增益为kdi=5.00和kpi=6.25.因此,慢时标系统的带宽为6.2 rad/s,慢时标和快时标系统的分解是合理的. ESO估计器的极点配置在ω0=20 rad/s,使其足够快,此时估计器增益为β1=3ω0, β2=3ω02, β3=ω03. TD的参数设置为r11=r12=3 000, h110=h120=0.04, r21=1 500, h210=0.03, r22=2 000, h220=0.04. NPD的参数设置为αp1=0.3, αd1=0.5, δp1=0.2, δd1=0.7, αp2=0.2, αd2=0.4, δp2=0.2和δd2=0.9. LQR的权系数矩阵选择为
$ \begin{array}{*{20}{c}} {{\mathit{\boldsymbol{Q}}_{\rm{f}}} = {\rm{diag}}\left( {100,10,10,10,10,10,10,10} \right),}\\ {{\mathit{\boldsymbol{R}}_{\rm{f}}} = {\rm{diag}}\left( {100,10} \right).} \end{array} $ |
机械臂的运动轨迹设计为
$ {\theta _i} = \left\{ \begin{array}{l} \frac{{{a_i}}}{2}\left[ {\sin \left( {{\omega _i}t - \frac{{\rm{ \mathsf{ π} }}}{2}} \right) + 1} \right],\;\;\;\;\;\;{\omega _i}t \le {\rm{ \mathsf{ π} ;}}\\ {a_i},\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;{\omega _i}t > {\rm{ \mathsf{ π} ;}} \end{array} \right.i = 1,2. $ |
其中ai和ωi为期望的最终角位置和转动速度.
3.2 末端负载的估计性能RLS参数设置为P0=2 000和mp0=m2,其中m2是预估负载质量.真实的负载质量为8.25 kg,因此,负载的不确定量为ΔMp=2m2=5.5 kg.末端负载估计器的性能如图 3所示.
其中黑色实线表示真实的负载质量,蓝色点划线表示预估负载质量,红色点线为负载估计器估计得到的负载质量.从图 3中可以看出,负载估计器以预估负载质量作为估计初值,当负载不确定量较大时,初始误差比较大,但估计值会向负载真值方向迅速变化,出现短暂的超调,并快速收敛到真值,收敛到5%误差的时间<0.2 s.出现较大超调的主要原因是:运动初始阶段,关节转动的角度和角速度、臂杆振动的模态坐标值都很小,Φ≈0,对负载质量的估计近似奇异,误差较大.通常,为了避免激起臂杆的振动,机械臂操纵负载机动的过程很缓慢,因此,可以认为负载估计收敛速度足够快.
3.3 小末端负载不确定时的性能当末端负载的不确定性比较小时,如ΔMp=0.2m2=0.55 kg,系统的响应如图 4所示.其中,设计轨迹参数为ω1=ω2=1 rad/s、a1=π/3 rad/s、a2=π/4 rad.为了方便,AADRC和ADRC分别表示ADRC控制器中采用和没采用RSL算法估计负载质量并进行补偿.作为对比,仿真中同时给出文献[15]中的计算力矩控制器(Computed torque controller, CTC)的响应.从图 4中可以看出,如果负载的不确定性比较小,AADRC和ADRC的性能基本一致.这主要是由于ADRC控制器本身就有一定的干扰抑制能力.采用CTC时,θ1和θ2都出现了明显的超调,且稳定时间较长.
当机械臂的运动速度增加时,如ω1=ω2=5 rad/s,第1节连杆的响应基本一致,而第2节连杆的响应却明显不同.从图 5中可以看到,采用ADRC时,θ2的超调量大于采用AADRC的,振动衰减的速度也比较慢.进一步比较图 4和图 5,机械臂运动速度的增加也导致了角度的超调量的增加.采用CTC时,θ1和θ2的超调也随着角速度增加而增加.
当末端负载不确定量增加时,如ΔMp=5.5 kg,系统的响应如图 6所示.即使是在机械臂低速运动时(ω1=ω2=1 rad/s),第2节臂杆的响应也明显不同.在对末端负载进行估计和补偿后,θ2迅速趋于稳定.如果只采用ADRC,则θ2存在明显的振荡.但是,末端负载不确定性的增加对第1节臂杆的影响很小.负载不确定性的增加也导致CTC的性能恶化,特别是θ2,超调量达到了30%.
如果机械臂的运动速度增加,单独采用ADRC的响应性能更加恶化,如图 7所示.比较图 6和图 7,采用ADRC控制,在负载不确定增加时,随着机械臂运动速度的增加,θ1的响应也明显的不同.如果负载质量不确定性得到补偿,机械臂速度增加对系统性能没有明显影响.采用CTC时,θ2的响应性能也进一步恶化,然而θ1并没有出现超调,但相比于其他两个控制器,有一定的滞后,这说明在这样的参数下,关节1的控制器构成了欠阻尼系统.
在不同速度下,系统响应随着负载不确定性的变化见图 8.其中,ω=ω1=ω2∈[1, 2, 3, 4, 5] rad/s,ΔMp=0.2 kg, k=1, 2, …, 10.均方差(mean square error)定义为
$ {\rm{MSE}}\left( x \right) = \sqrt {\frac{1}{{{t_{\rm{f}}}}}\int_0^{{t_{\rm{f}}}} {{{\left( {{x_d} - x} \right)}^2}{\rm{d}}t} } = \sqrt {\frac{1}{N}\sum\limits_N {{{\left( {{x_d} - x} \right)}^2}} } , $ |
其中,tf是仿真时长,N是采样数量.从图中可以看出,无论采用AADRC、ADRC,还是CTC,θ1和θ2的均方差都随ω增加而增加.这主要是由于随着运动速度的增加,超调量也增加.采用ADRC,θ1的均方差随着负载不确定性的增加并不明显,θ2的均方差变化显著,特别是运动速度较大时.采用CTC时,在负载质量不确定度较小时,θ1的均方差比采用ADCRC和AADRC时大,但随着负载不确定性的增加而减小,在负载不确定性较大时,其性能优于ARDC,但不如AADRC; θ2的均方差随着负载不确定性的增加迅速增加,增速比ADRC略缓.总体看来,在负载质量得到估计和补偿,即采用AADRC时,系统响应对负载的变化和速度变化具有鲁棒性.
4 结论1) 针对多柔性臂杆机械臂的控制问题,本文提出了一种新的控制器结构.首先采用奇异摄动理论将系统分解为快时标和慢时标两个子系统.慢时标子系统采用自适应自抗扰控制,快时标子系统采用线性二次型控制器.
2) 自适应自抗扰控制器采用微分跟踪器获得期望角度的角速度和角加速度,采用状态扩张估计器获得估计真实的角速度和角加速度及干扰,采用迭代最小二乘算法估计负载的不确定性,采用非线性比例微分控制器保证系统的鲁棒性.
3) 仿真结果表明,无论采用AADRC,还是采用ADRC,末端负载的不确定性对臂杆振动和关节转动的控制精度的影响随关节转动速度的增加而变得更加明显.关节2的转动角度控制精度和臂杆2的振动受末端负载的不确定性的影响比关节1和臂杆1更为明显.
4) 采用迭代最小二乘算法估计负载的不确定性并进行补偿后,AADRC相比于ADRC,对末端负载不确定性的变化和关节转动速度的变化都具有更好的鲁棒性.
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